Parcourir la source

Obtain min password length from utils script

Bob Mottram il y a 8 ans
Parent
révision
97643c2306
1 fichiers modifiés avec 2 ajouts et 2 suppressions
  1. 2
    2
      src/freedombone-image

+ 2
- 2
src/freedombone-image Voir le fichier

@@ -78,10 +78,10 @@ DEFAULT_DOMAIN_NAME="${PROJECT_NAME}.local"
78 78
 # Minimum number of characters in a password
79 79
 MINIMUM_PASSWORD_LENGTH=10
80 80
 if [ -f /usr/local/bin/${PROJECT_NAME} ]; then
81
-	MINIMUM_PASSWORD_LENGTH=$(cat /usr/local/bin/${PROJECT_NAME} | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
81
+	MINIMUM_PASSWORD_LENGTH=$(cat /usr/local/bin/${PROJECT_NAME}-utils-passwords | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
82 82
 else
83 83
 	if [ -f /usr/bin/${PROJECT_NAME} ]; then
84
-		MINIMUM_PASSWORD_LENGTH=$(cat /usr/bin/${PROJECT_NAME} | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
84
+		MINIMUM_PASSWORD_LENGTH=$(cat /usr/bin/${PROJECT_NAME}-utils-passwords | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
85 85
 	fi
86 86
 fi
87 87